Jawab:
= 0
opsi E
pembahasan :
g(x) = tan(πx- π)
lim x->1 g(x) = tan (π(1) -π) =
tan 0 =
0
lim x->1 {f(x) × g(x)} =
lim x->1 f(x) × lim x->1 g(x) =
? × 0 =
(apapun yang dikali dengan 0 = 0)
lihat lampiran.
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Jawab:
= 0
opsi E
pembahasan :
g(x) = tan(πx- π)
lim x->1 g(x) = tan (π(1) -π) =
tan 0 =
0
lim x->1 {f(x) × g(x)} =
lim x->1 f(x) × lim x->1 g(x) =
? × 0 =
0
(apapun yang dikali dengan 0 = 0)
lihat lampiran.