hanieproz
14.luas selimut tabung= 2x π x r x t 2464=2 x 22/7 x r x t 2464/2 x 7/22=r x t r x t=392 t=2r 2r²=392 r²=196 r=14 luas permukaan bola=4 π x r² =4 x 22/7 x 14 x 14 =2464 (A)
15.r= 42/2=21 t=√29²-21² t=√841-411=√400=20 volume kerucut= 1/3 x π x r² x t v=1/3 x 22/7 x 21 x 21 x 20 v=9240 (C)
16.v silinder=π x r² x t 352=22/7 x r² x 7 352 x 7/22 x1/7=r² r²=16 r=√16=4 (D)
2464=2 x 22/7 x r x t
2464/2 x 7/22=r x t
r x t=392
t=2r
2r²=392
r²=196
r=14
luas permukaan bola=4 π x r²
=4 x 22/7 x 14 x 14
=2464 (A)
15.r= 42/2=21
t=√29²-21²
t=√841-411=√400=20
volume kerucut= 1/3 x π x r² x t
v=1/3 x 22/7 x 21 x 21 x 20
v=9240 (C)
16.v silinder=π x r² x t
352=22/7 x r² x 7
352 x 7/22 x1/7=r²
r²=16
r=√16=4 (D)
semoga membantu :)