[tex] \frac{1}{2} d1 = \sqrt{( { \frac{k}{4}) }^{2} - ( { \frac{d2}{2} )}^{2} } \\ \sqrt{( { \frac{68}{4} )}^{2} - ( { \frac{30}{2}) }^{2} } = \sqrt{ {17}^{2} - {15}^{2} } \\ \sqrt{289 - 225} = \sqrt{64} = 8 \: cm\\ \\ Luas \: belah \: ketupat \\ \frac{1}{2} d1 \times d2 \\ 8 \: cm \times 30 \: cm \\ 240 \: {cm}^{2} \: (b)[/tex]
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[tex] \frac{1}{2} d1 = \sqrt{( { \frac{k}{4}) }^{2} - ( { \frac{d2}{2} )}^{2} } \\ \sqrt{( { \frac{68}{4} )}^{2} - ( { \frac{30}{2}) }^{2} } = \sqrt{ {17}^{2} - {15}^{2} } \\ \sqrt{289 - 225} = \sqrt{64} = 8 \: cm\\ \\ Luas \: belah \: ketupat \\ \frac{1}{2} d1 \times d2 \\ 8 \: cm \times 30 \: cm \\ 240 \: {cm}^{2} \: (b)[/tex]