Question

Mohon bantuan nya ya
turunkan rumus empiris bahan mineral yg mempunyau komposisi berikut :
a). ZnSO4 = 56,14% , H2O = 43,86%
b). mgO= 27,6% , SiO2 = 60,70% , H2O = 12,14%
c). Na = 12,10% ,Al=14,19% ,Si = 22,14% , O =42,09% , H2O = 9,48%

Answer 1

Gunakan perbandingan antar mol zal (%massa:Ar/Mr)
a). n ZnSO4 : n H2O
= 56,14/161,5 : 43,86/18
= 0,348 :2,4367 = 1: 7
ZnSO4.7H2O

b) n MgO : n SiO2 : n H2O
= 27,6/40 : 60,70/60 : 12,14/18
= 0,69 : 1,011 : 0,674
= 1,02 : 1,5 : 1 = 2 :3:2
2MgO.3SiO2.2H2O

c) n Na : n Al : n Si : n O : n H2O
= 12,10/23 : 14,19/27 : 22,14/28 : 42,09/16 : 9,48/18
=0,526 :0,5256 : 0,791 : 2,63 : 0,5267
= 1 : 1 : 1,5 : 5 : 1
= 2:2:3:10:2
Na2Al2Si3O10.2H2O