Jawaban:
4.
Pipa organa tertutup
f3 = 150Hz
Untuk harmonik ketiga L = 3/4 λ maka λ3 = 4/3 L
v = 340 m/s
L = ?
Harmonik ke tiga
λ = 4/3 L
v = λf
v = 4/3 L f
L = 3/4 v/f
L = 3/4 340/150 = 1,7 m
5.
Pipa tertutup
Pada harmonik kelima
L = 5/4 λ
λ5 = 4/5 L
f5 = 990 Hz
v =λ f
340 = 4/5 L * 990
L = 340/990 *5/4 = 0,43 m
Pipa terbuka
L = 5/2 λ
λ5 = 2/5 L = 2/5 * 0,43 = 0,172 m
f5 = ?
v =λf
f = v/λ = 340/0,172 = 1976,7 Hz
6.
fn = 1310
fn+1 = 1834
fn+2 = 2358
setelah dicoba dibagi 1,2,3,4,5, dst ternyata frekuensi di atas tidak jadi pecahan dimulai
angka 5, jadi hasil baginya 262 jadi frekuensi di atas dibagi 262 :
fn : fn+1 : fn+2 = 5:7:9 (ciri pipa organa tertutup)
b.
fo = ?
fo:f1:f2 = 1:3:5
f5 = 1310
fo/f2 = 1/5
fo = f2/5 = 1310/5 = 262 Hz
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Jawaban:
4.
Pipa organa tertutup
f3 = 150Hz
Untuk harmonik ketiga L = 3/4 λ maka λ3 = 4/3 L
v = 340 m/s
L = ?
Harmonik ke tiga
λ = 4/3 L
v = λf
v = 4/3 L f
L = 3/4 v/f
L = 3/4 340/150 = 1,7 m
5.
Pipa tertutup
Pada harmonik kelima
L = 5/4 λ
λ5 = 4/5 L
f5 = 990 Hz
v =λ f
340 = 4/5 L * 990
L = 340/990 *5/4 = 0,43 m
Pipa terbuka
L = 5/2 λ
λ5 = 2/5 L = 2/5 * 0,43 = 0,172 m
f5 = ?
v =λf
f = v/λ = 340/0,172 = 1976,7 Hz
6.
fn = 1310
fn+1 = 1834
fn+2 = 2358
setelah dicoba dibagi 1,2,3,4,5, dst ternyata frekuensi di atas tidak jadi pecahan dimulai
angka 5, jadi hasil baginya 262 jadi frekuensi di atas dibagi 262 :
fn : fn+1 : fn+2 = 5:7:9 (ciri pipa organa tertutup)
b.
fo = ?
fo:f1:f2 = 1:3:5
f5 = 1310
fo/f2 = 1/5
fo = f2/5 = 1310/5 = 262 Hz
Penjelasan: