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Verified answer
M etanol (C2H5OH) = 25 gramV etanol = 200 mL
ρ benzena = 0,879 gr/mL
Mr etanol = 2 Ar C + 6 Ar H + Ar O
Mr etanol = 2(12) + 6(1) + 16
Mr etanol = 46
M etanol = (m etanol / Mr etanol) × (1000 / V benzena)
M etanol = ( 25 gram / 46 ) × ( 1000 / 200 mL )
M etanol = 2,7174 M