November 2019 1 62 Report
Misalkan
f(5x + 2) \geqslant f(5x) + 2 \\ dan \\ f(5x + 1) \leqslant f(5x) + 1
untuk setiap bilangan x. jika
g(x) = f(x) - 2 \\ dan \\ f(5) = \frac{1}{(1)(2)} + \frac{1}{(2)(3)} + \frac{1}{(3)(4)} + ..... + \frac{1}{(2018)(2019)}
hitunglah nilai dari g(7)!

#geser kesamping untuk lebih jelasnya

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