Question

Misalkan f(x) = (x2-2x) dan f' menyatakan turunan pertama f' terhadap x,hitunglah nilai f' (2)

Answer 1

F' = 2x- 2 . √(x²-1) + (x²-2x) . 1/2 . (x²-1)^-1/2 . 2x
f'(2) = 4-2 . √4-1 + 4-4 ...
= 2√3

Answer 2

F(x) = (x²-2x)(x²-1)^1/2
f ' (x) = (2x-2)√(x²-1) + (x²-2x)(x)
                                    √(x² - 1)
f'(2) = (4-2)√(4-1) + ((4-4)4)/√(4-1)
       = 2√3 + 0
       = 2√3