Question

Misal f(x^2-bx)=6-x , f(4)=5
maka b=...

Answer 1

Nilai x :
6 - x = 5
   - x = 5 - 6
   - x = -1
     x = 1

Maka :
f(x² - bx) = 6 - x
f(1² - b(1)) = 6 - 1
f(1 - b) = 5

Jadi, nilai b :
1 - b = 4
   - b = 4 - 1
   - b = 3
     b = -3

Semoga membantu ^_^

Answer 2

X = 6 - 5
x = 1

b = -4 + 1
b = -3