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katoda: Ni²⁺ + 2e --> Ni
I = 1,93 A
massa endapan = 0,58 gr
Ar Ni = 58
F = 96500
t = ?
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t = (massa endapan x F) / (e x I)
e = Ar Ni / perubahan biloks = 58 / 2 = 29
t = (0,58 x 96500) / (29 x 1,93)
t = 1000 sc (C)