Jawaban:
D
Penjelasan dengan langkah-langkah:
metode integral substitusi
note :
| adalah simbol integral
| (4x + 3)(4x² + 6x - 9)^9 dx
let u = 4x² + 6x - 9
du = 8x + 6 dx
du = 2(4x + 3) dx
= 1/2 | u^9 du
= 1/2 (u^10/10) + C
= u^10/20 + C
= (1/20)(4x² + 6x - 9)^9 + C
SEMOGA MEMBANTU :)
Penyelesaian:
int (4x + 3) (4x^2 + 6x - 9)^9 dx
misal
u = 4x^2 + 6x - 9
du = 8x + 6
dx = du/8x + 6
int (4x + 3) u^9 . du/8x + 6
int (4x + 3) u^9 . du/2(4x + 3)
1/2 int u^9 . du
= 1/2 . 1/10 . u^10 + C
= 1/20 . u^10 + C
= 1/20 (4x^2 + 6x - 9)^10 + C
==================
Kelas: 11
Mapel: Matematika
Bab: Integral Tak Tentu Fungsi Aljabar
Kode: 11.2.10
Kata Kunci: Integral Subtitusi
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Verified answer
Jawaban:
D
Penjelasan dengan langkah-langkah:
metode integral substitusi
note :
| adalah simbol integral
| (4x + 3)(4x² + 6x - 9)^9 dx
let u = 4x² + 6x - 9
du = 8x + 6 dx
du = 2(4x + 3) dx
= 1/2 | u^9 du
= 1/2 (u^10/10) + C
= u^10/20 + C
= (1/20)(4x² + 6x - 9)^9 + C
SEMOGA MEMBANTU :)
Penyelesaian:
int (4x + 3) (4x^2 + 6x - 9)^9 dx
misal
u = 4x^2 + 6x - 9
du = 8x + 6
dx = du/8x + 6
int (4x + 3) (4x^2 + 6x - 9)^9 dx
int (4x + 3) u^9 . du/8x + 6
int (4x + 3) u^9 . du/2(4x + 3)
1/2 int u^9 . du
= 1/2 . 1/10 . u^10 + C
= 1/20 . u^10 + C
= 1/20 (4x^2 + 6x - 9)^10 + C
==================
Detil Jawaban
Kelas: 11
Mapel: Matematika
Bab: Integral Tak Tentu Fungsi Aljabar
Kode: 11.2.10
Kata Kunci: Integral Subtitusi