Question

método de sustitución de
5x-2y=1
3x+5y=13
xfvor lo necesito urgente ​

Answer 1

Respuesta:

primera

5x-2y=1

5×-2y-1=1-1

5×-2y-1=0

segunda

3x+5y=13

3×+5y-13=13-13

3×+5y-13=0

Answer 2

Respuesta:

x = 1

y = 2

Explicación paso a paso:

5x - 2y = 1

3x + 5y = 13

Despejemos x de 5x - 2y = 1:

5x - 2y = 1

5x - 2y + 2y = 1 + 2y

5x = 1 + 2y

x = [tex]\frac{1+2y}{5}[/tex]

Sustituimos x = [tex]\frac{1+2y}{5}[/tex]:

[tex]3*\frac{1+2y}{5} +5y[/tex]

[tex]\frac{3(2y+1)}{5} +5y[/tex]

[tex]\frac{(1+2y) * 3}{5} +\frac{5y*5}{5}[/tex]

[tex]\frac{(1+2y) * 3}{5} +\frac{25y}{5}[/tex]

[tex]\frac{3(1+2y)+25y}{5}[/tex]

[tex]\frac{3+6y+25y}{5}[/tex]

[tex]\frac{3+31y}{5} =13[/tex]

Despejamos y de [tex]\frac{3+31y}{5} =13[/tex]:

[tex]\frac{3+31y}{5} =13[/tex]

[tex]\frac{5(3+31y)}{5} =13*5[/tex]

[tex]3+31y =65[/tex]

[tex]31y =65-3[/tex]

[tex]31y =62[/tex]

[tex]y =62/31[/tex]

[tex]y =2[/tex]

Ahora realizamos [tex]x=\frac{1+2y}{5}[/tex]:

[tex]x=\frac{1+2y}{5}[/tex]

[tex]x=\frac{1+2*2}{5}[/tex]

[tex]x=\frac{1+4}{5}[/tex]

[tex]x=\frac{5}{5}[/tex]

x = 1