Respuesta:
[tex]3x + 2y = 3 ....(I)[/tex]
[tex]-x + 5y = 16....(II)[/tex]
[tex]3x + 2y = 3[/tex]
[tex]3x = 3 - 2y[/tex]
[tex]x =\frac{3-2y}{3}[/tex]
[tex]-x + 5y = 16[/tex]
[tex]-(\frac{3-2y}{3}) + 5y = 16[/tex]
[tex]\frac{-3 + 2y}{3} = 16 - 5y[/tex]
[tex]-3 +2y = 3(16-5y)[/tex]
[tex]-3 + 2y = 48 - 15y[/tex]
[tex]2y + 15y = 48 + 3[/tex]
[tex]17y = 51[/tex]
[tex]y = \frac{51}{17}[/tex]
[tex]y= 3[/tex]
[tex]3x + 2(3) = 3[/tex]
[tex]3x + 6 = 3[/tex]
[tex]3x = 3 - 6[/tex]
[tex]3x = -3[/tex]
[tex]x=\frac{-3}{3}[/tex]
[tex]x = -1[/tex]
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Respuesta:
[tex]3x + 2y = 3 ....(I)[/tex]
[tex]-x + 5y = 16....(II)[/tex]
✨Despejamos "x" en (I)
[tex]3x + 2y = 3[/tex]
[tex]3x = 3 - 2y[/tex]
[tex]x =\frac{3-2y}{3}[/tex]
⨠ Reemplazamos en (II)
[tex]-x + 5y = 16[/tex]
[tex]-(\frac{3-2y}{3}) + 5y = 16[/tex]
[tex]\frac{-3 + 2y}{3} = 16 - 5y[/tex]
[tex]-3 +2y = 3(16-5y)[/tex]
[tex]-3 + 2y = 48 - 15y[/tex]
[tex]2y + 15y = 48 + 3[/tex]
[tex]17y = 51[/tex]
[tex]y = \frac{51}{17}[/tex]
[tex]y= 3[/tex]
⇒Hallamos "x":
[tex]3x + 2y = 3[/tex]
[tex]3x + 2(3) = 3[/tex]
[tex]3x + 6 = 3[/tex]
[tex]3x = 3 - 6[/tex]
[tex]3x = -3[/tex]
[tex]x=\frac{-3}{3}[/tex]
[tex]x = -1[/tex]