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T1 = 300 K
T2 = 400 K
W = 10⁴ J
Ditanyakan : Q ?
Dijawab :
η = (1-T1/T2)
= (1 - 300/400)
= (1 - 3/4)
= 1/4
= 0,25
Kalor :
η = W/Q
Q=W/η
= 10⁴/0,25
= 4x10⁴ J