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contohnya :
x2-10x+25 =0
(x-5)2=0
x=5
yang angka 2 dibelakang itu kuadrat
Tentukan akar-akar dari persamaan kuadrat berikut :
a.) x² - x - 6 = 0
b.) 6x² + 5x - 6 = 0
jawab :
1.) a. x² - x - 6 = 0
(x+2) (x-3)
x = -2 ∨ x = 3
b. 6x² + 5x - 6 = 0
(2x+3) (3x-2)
2x+3=0 x = 2/3
2x= -3 ∨
x=-3/2