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2'log 3 = b
7'log 2 . 2'log 3 = 7'log 3 = ab
2'log 98 / 2'log 6
= (2'log (2 × 7^2)) / 2'log (2 × 3)
= (2'log 2 + 2'log 7^2) / (2'log 2 + 2'log 3)
= (1 + 2/a) / (1 + b)
= (a + 2) / (a(1 + b))
= (a + 2) / (a + ab)