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yg satunya 0,001 M, yg satunya lagi 0,1 M
konsentrasi H+ = M.a
= 0,001 * 1
= 0,001
= 10^ -3
Ph = -log kons. H+
= - log 10^ -3
= 3
konsentrasi H+ = M.a
= 0,1 * 1
= 0,1
= 10^ -1
Ph = -log kons. H+
= - log 10^ -1
= 1
pH = - log H positif
H = 0,001 M = 1x10^-3 M
H = 0,1 M = 1x10^1 M
pH = - log 1x10^-3 = 3
pH = - log 1x10^1 = 1
jadi karena perbedaan mollalnya