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k + k + l = -b/a = 5
2k + l = 5
l = 5 - 2k <--------------- persamaan pertama
k.k + k.l + k.l = c/a = 8
k² + 2kl = 8 <--------------- persamaan kedua
k(k + 2l) = 8
k(k + 2(5 - 2k)) = 8
k(k + 10 - 4k) = 8
k(10 - 3k) = 8
3k² - 10k + 8 = 0
(k - 2)(3k - 4) = 0
Karena bulat k = 2
l = 5 - 2(2)
l = 1
Nilai n = - (k . k .l)
-----------> - (2 . 2 . 1) = - 4 [E]