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√(a+x) + √(a-x) = √2a
[ √a+x + √a-x ]² = [ √2a ]²
(√a+x)² + 2(√a+x)(√a-x) + (√a-x)² = 2a
a + x + 2√(a+x)(a-x) + a - x = 2a
2√a²-x² = 0
4(a²-x²) = 0
a²-x² = 0
x² = a²
x = ± a