Question

Membuktikan Sifat Komutatif a. Diketahui: f(x) = 3x + 2 g(x)=x-2 (fog)(x) = f(g(x)) = f( ......... ) = 3(.........) + 2 = .......... +2 ....... (gof)(x) = g(f(x)) = g( .......... ) =(.. .)-2 + Diperoleh fog #gof 2

tolong jawab pke cara ya ka. ​

Answer 1

• f(x) = 3x + 2
• g(x) = x - 2

Sehingga,

A. (fog)(x) = f(g(x))

• (fog)(x) = f(x - 2)
• (fog)(x) = 3(x - 2) + 2
• (fog)(x) = (3x - 6) + 2
• (fog)(x) = 3x - 6 + 2
• (fog)(x) = 3x - 4

B. (gof)(x) = g(f(x))

• (gof)(x) = g(3x + 2)
• (gof)(x) = (3x + 2) - 2
• (gof)(x) = 3x + 2 - 2
• (gof)(x) = 3x + 0
• (gof)(x) = 3x

Kesimpulan,

• Terbukti bahwa (fog)(x) # (gof)(x).