Megan was walking along a straight road. She met an oncoming car and she asked the driver, “Did you overtake a cyclist just now?” “Yes, 10 minutes ago,” the driver replied. After walking for another 10 minutes, Megan met the cyclist. Given that the cyclist’s speed was 4 times Megan’s walking speed, how many times of Megan’s speed was the driver’s speed
Jawaban:
Let's start by assuming that Megan's walking speed is x. We know that the cyclist's speed is 4 times Megan's walking speed, so the cyclist's speed is 4x.
Let's also assume that the driver's speed is y. We want to find out how many times the driver's speed is Megan's speed, or y/x.
We know that the driver overtook the cyclist 10 minutes before meeting Megan. In those 10 minutes, the driver traveled the distance that the cyclist covered in 20 minutes (10 minutes before meeting the driver and 10 minutes after). So we can write:
y * (10/60) = 4x * (20/60)
Simplifying this equation, we get:
y = 8x
Therefore, the driver's speed is 8 times Megan's walking speed. So the answer to the question is 8.