Me pueden syudar
fx=(ln(3x^3))^5
f'x=?
fx=(ln(3x^3))^5
f'x=?
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d/dx (In(x)) =1/x
f°(x)= 5(In(3x³))⁴·(In(3x³))°
f°(x)=5(In(3x³))⁴·(3x³°/3x³)
f°(x)=5(In(3x³))⁴·(9x²/3x³)
f⁰(x)=5(In(3x³))⁴·(3/x)
f⁰(x)=(15(In⁴(3x³))/x
Espero que sirva!Saludos!