A D.P B
[tex] \frac{a}{5} = \frac{6}{3} = \frac{4}{b} \\ [/tex]
⇒Hallamos el valor de "a" :
[tex] \frac{a}{5} = \frac{6}{3} \\ a = \frac{6}{3} \times 5 \\ a = \frac{30}{3} \\ \boxed{a = 10}[/tex]
⇒Hallamos el valor de "b" :
[tex] \frac{6}{3} = \frac{4}{b} \\ 6 \times b = 4 \times 3 \\ 6 \times b = 12 \\ b = \frac{12}{6} \\ \boxed{b = 2}[/tex]
⇒Calculamos "a + b" :
[tex]→\boxed{a + b = 10 + 2 = 12}[/tex]
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Verified answer
☆ PROBLEMA 9
A D.P B
[tex] \frac{a}{5} = \frac{6}{3} = \frac{4}{b} \\ [/tex]
⇒Hallamos el valor de "a" :
[tex] \frac{a}{5} = \frac{6}{3} \\ a = \frac{6}{3} \times 5 \\ a = \frac{30}{3} \\ \boxed{a = 10}[/tex]
⇒Hallamos el valor de "b" :
[tex] \frac{6}{3} = \frac{4}{b} \\ 6 \times b = 4 \times 3 \\ 6 \times b = 12 \\ b = \frac{12}{6} \\ \boxed{b = 2}[/tex]
⇒Calculamos "a + b" :
[tex]→\boxed{a + b = 10 + 2 = 12}[/tex]
☆ RESPUESTA:
[tex] \boxed{a + b = 12}[/tex]