Question

me podrían resolver esto por favor​

Answer 1

Verified answer

PROCEDIMIENTOS:

[tex]3+\frac{x+1}{2} =3x-\frac{5-x}{4} \\\\12+2(x+1)=12x-(5-x)\\\\12+2x+2=12x-5+x\\\\14+2x=13x-5\\\\2x-13x=-5-14\\\\-11x=-19\\\\x=\frac{19}{11}[/tex]

Resultado: [tex]x=\frac{19}{11}[/tex]

[tex]\frac{3}{4} (\frac{5}{3} x+\frac{1}{2} )=3(\frac{1}{2} x+\frac{1}{3} )\\\\\frac{5}{4} x+\frac{3}{8} =\frac{3}{2} x+1\\\\10x+3=12x+8\\\\10x-12x=8-3\\\\-2x=5\\\\x=-\frac{5}{2}[/tex]

Resultado: [tex]x=-\frac{5}{2}[/tex]

[tex]-2(3x+2)=5(x-4)\\\\-6x-4=5x-20\\\\-6x-5x=-20+4\\\\-11x=-16\\\\x=\frac{16}{11}[/tex]

Resultado: [tex]x=\frac{16}{11}[/tex]

Atte: Sabius95