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Fig 1 donde P=Perímetro
P=a + 2a + 7 + a + 4 + a = 5 a + 11
P= 5a+11
Fig 2
Debido a que tiene 2 pares de lados iguales sería
P= 2 (b+5) + 2 (1b/2) = 2b+ 10 + b = 3b+10
P=3b+10