Respuesta:
[tex] 2). \: {x}^{2} - 1 = (x + 1)( x - 1) \\ 4). \: 4 {x}^{2} - 36 {y}^{2} = {(2x)}^{2} - {(6y)}^{2} \\ = (2x + 6y)(2x - 6y) \\ 6). \: {x}^{2} - \frac{16}{49} = {x}^{2} - ( \frac{4}{7} ) {}^{2} \\ = (x + \frac{4}{7} )(x + \frac{4}{7} )[/tex]
[tex]8). \: 16 {a}^{2} {b}^{2} - {c}^{2} = {(4ab)}^{2} - {c}^{2} \\ = (4ab + c)(4ab - c) \\ 10). \: {x }^{2} - \frac{1}{16} = {x}^{2} - {( \frac{1}{4} )}^{2} \\ = (x - \frac{1}{4} )(x + \frac{1}{4} )[/tex]
mi coronaaaaaa ✌️
Hola Vanillanax espero que te encuentres bien !!
Explicación paso a paso:
x² - 1 = ( x + 1 ) ( x − 1 )
4x² - 36y² = 4 ( x + 3 y ) ( x − 3 y )
x² - [tex]\frac{16}{49}[/tex] = ( x + [tex]\frac{4}{7}[/tex] ) ( x − [tex]\frac{4}{7}[/tex] )
16a²b² - c² = ( 4 ab + c ) ( 4 a b − c )
x² - [tex]\frac{1}{16}[/tex] = ( x + [tex]\frac{1}{4}[/tex] ) ( x − [tex]\frac{1}{4}[/tex] )
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Respuesta:
[tex] 2). \: {x}^{2} - 1 = (x + 1)( x - 1) \\ 4). \: 4 {x}^{2} - 36 {y}^{2} = {(2x)}^{2} - {(6y)}^{2} \\ = (2x + 6y)(2x - 6y) \\ 6). \: {x}^{2} - \frac{16}{49} = {x}^{2} - ( \frac{4}{7} ) {}^{2} \\ = (x + \frac{4}{7} )(x + \frac{4}{7} )[/tex]
[tex]8). \: 16 {a}^{2} {b}^{2} - {c}^{2} = {(4ab)}^{2} - {c}^{2} \\ = (4ab + c)(4ab - c) \\ 10). \: {x }^{2} - \frac{1}{16} = {x}^{2} - {( \frac{1}{4} )}^{2} \\ = (x - \frac{1}{4} )(x + \frac{1}{4} )[/tex]
mi coronaaaaaa ✌️
Verified answer
Respuesta:
Hola Vanillanax espero que te encuentres bien !!
Explicación paso a paso:
x² - 1 = ( x + 1 ) ( x − 1 )
4x² - 36y² = 4 ( x + 3 y ) ( x − 3 y )
x² - [tex]\frac{16}{49}[/tex] = ( x + [tex]\frac{4}{7}[/tex] ) ( x − [tex]\frac{4}{7}[/tex] )
16a²b² - c² = ( 4 ab + c ) ( 4 a b − c )
x² - [tex]\frac{1}{16}[/tex] = ( x + [tex]\frac{1}{4}[/tex] ) ( x − [tex]\frac{1}{4}[/tex] )
Espero haberte ayudado :)
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