Respuesta:
Se reemplazan los valores y se obtiene:
a. 5[tex](2)^{2}[/tex]+2(-1)(3)+3(1)
= 5 * 4 - 6 + 3
= 20 - 6 + 3
= 17
b. 3[tex](2)^{2}[/tex]-2(2)(3)+3(5)
= 3([tex]2^{2}[/tex]-2*2+5)
= 3(4-4+5)
= 3 * 5
= 15
c. -5(2)(-1)+1
= 10 + 1
= 11
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Verified answer
Respuesta:
Se reemplazan los valores y se obtiene:
a. 5[tex](2)^{2}[/tex]+2(-1)(3)+3(1)
= 5 * 4 - 6 + 3
= 20 - 6 + 3
= 17
b. 3[tex](2)^{2}[/tex]-2(2)(3)+3(5)
= 3([tex]2^{2}[/tex]-2*2+5)
= 3(4-4+5)
= 3 * 5
= 15
c. -5(2)(-1)+1
= 10 + 1
= 11