Me ayudan seria de mucha ayuda
desarrollar y reducir
2(4a+3)-(3a-1)-(2a+2)+7a
desarrollar y reducir
2(4a+3)-(3a-1)-(2a+2)+7a
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2•4a+ 2•3- 3a+ 1- 2a- 2+ 7a=
8a+ 6- 3a + 1- 2a -2 + 7a=
8a- 3a- 2a+ 7a + 6+ 1- 2=
3a+ 7a+ 7-2= 10a+ 5;
Respuesta: =10a+5