Respuesta:
a)
[tex] \frac{ {x}^{3} + 5 {x}^{2} + 6x }{ {x}^{2} + 4x + 4 } \\ = \frac{(x)( {x}^{2} + 5x + 6) }{(x + 2) {}^{2} } \\ = \frac{(x)(x + 3)(x + 2)}{ {(x + 2)}^{2} } \\ = \frac{(x)(x + 3)}{x + 2} [/tex]
b)
[tex] \frac{2 {x}^{3}y - 2 {x}^{2} {y}^{2} }{8 {x}^{3} {y}^{2} - 4 {x}^{2} {y}^{3} } \\ = \frac{(2 {x}^{2}y)(x - y) }{(2 {x}^{2} y)(4xy - 2 {y}^{2} ) } \\ = \frac{x - y}{4xy - 2 {y}^{2} } \\ = \frac{x - y}{(2y)(2x - y)} [/tex]
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Respuesta:
a)
[tex] \frac{ {x}^{3} + 5 {x}^{2} + 6x }{ {x}^{2} + 4x + 4 } \\ = \frac{(x)( {x}^{2} + 5x + 6) }{(x + 2) {}^{2} } \\ = \frac{(x)(x + 3)(x + 2)}{ {(x + 2)}^{2} } \\ = \frac{(x)(x + 3)}{x + 2} [/tex]
b)
[tex] \frac{2 {x}^{3}y - 2 {x}^{2} {y}^{2} }{8 {x}^{3} {y}^{2} - 4 {x}^{2} {y}^{3} } \\ = \frac{(2 {x}^{2}y)(x - y) }{(2 {x}^{2} y)(4xy - 2 {y}^{2} ) } \\ = \frac{x - y}{4xy - 2 {y}^{2} } \\ = \frac{x - y}{(2y)(2x - y)} [/tex]