Question

ME AYUDAN ME AYUDAN ES URGENTE

Answer 1

Resolución

[tex]x-\left(2x+1\right)=8-\left(3x+3\right)[/tex]

Resolvemos un lado

[tex]x-\left(2x+1\right)[/tex]

[tex]=x-2x-1[/tex]

[tex]=-x-1[/tex]

Ahora resolvemos el siguiente

[tex]8-\left(3x+3\right)[/tex]

[tex]=8-3x-3[/tex]

[tex]=-3x+5[/tex]

Por lo tanto

[tex]-x-1=-3x+5[/tex]

[tex]-x-1+1=-3x+5+1[/tex]

[tex]-x=-3x+6[/tex]

[tex]-x+3x=-3x+6+3x[/tex]

[tex]2x=6[/tex]

[tex]x=\frac{6}{2}[/tex]

[tex]x=3[/tex]

RPTA = "x" equivale 3  

Answer 2

Hola!!!

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[tex]x - (2x + 1) = 8 - (3x + 3) \\ - x + 1 = 11 - 3x \\ - x + 3x = 11 - 1 \\ 2x = 10 \\ x = 5[/tex]

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Saludos.