Question

ME AYUDAN CON ESTO POR FA

Answer 1

Verified answer

RESOLVER:

a) [tex]\frac{9}{4}+\frac{8}{3}[/tex]

MCM de [tex]4,3:12[/tex]

[tex]=\frac{27}{12}+\frac{32}{12}[/tex]

[tex]=\frac{27+32}{12}[/tex]

[tex]\boxed{=\frac{59}{12}}[/tex]

b) [tex]\frac{6}{5}+\frac{3}{4}[/tex]

MCM de [tex]5,4:20[/tex]

[tex]=\frac{24}{20}+\frac{15}{20}[/tex]

[tex]\boxed{=\frac{39}{20}}[/tex]

c) [tex]\frac{2}{5}-\frac{1}{10}[/tex]

MCM de [tex]5,10:10[/tex]

[tex]=\frac{4}{10}-\frac{1}{10}[/tex]

[tex]=\frac{4-1}{10}[/tex]

[tex]\boxed{=\frac{3}{10}}[/tex]

d) [tex]\frac{6}{4}-\frac{1}{2}[/tex]

Cancelamos [tex]\frac{6}{4}:\frac{3}{2}[/tex]

[tex]=\frac{3}{2}-\frac{1}{2}[/tex]

[tex]=\frac{3-1}{2}[/tex]

[tex]=\frac{2}{2}[/tex]

[tex]\boxed{=1}[/tex]

e) [tex]\frac{5}{3}-\frac{4}{6}[/tex]

Cancelamos [tex]\frac{4}{6}:\frac{2}{3}[/tex]

[tex]=\frac{5}{3}-\frac{2}{3}[/tex]

[tex]=\frac{5-2}{3}[/tex]

[tex]=\frac{3}{3}[/tex]

[tex]\boxed{=1}[/tex]

[tex]Buena\:suerte\:con\:tus\:tareas\::ProfeAndresFelipe :)[/tex]