Question

ME AYUDAN CON ESTO PLIS

Answer 1

Soy yo a la pediste ayuda y te ayudaré :D

1. [tex][(\frac{8}{10} )^{2} -(\frac{4}{10} )^{2} ]+ \sqrt{(\frac{7}{3} )^{3} }[/tex]

Pasos:

Quitar los parentesis: [tex](a)=a[/tex]

= [tex](\frac{8}{10} )^{2} -(\frac{4}{10} )^{2} +\sqrt{(\frac{7}{3} )^{3} }[/tex]

[tex](\frac{8}{10} )^{2} =\frac{4^{2} }{5^{2} }[/tex]

[tex](\frac{4}{10} )^{2} =\frac{2^{2} }{5^{2} }[/tex]

[tex]\sqrt{(\frac{7}{3} )^{3} } = \frac{7\sqrt{7} }{3 \sqrt{3} }[/tex]

= [tex]\frac{4^{2} }{5^{2} } -\frac{2^{2} }{5^{2} } +\frac{7\sqrt{7} }{3\sqrt{3} }[/tex]

Combinar las fracciones usando el minimo comun denominador: [tex]\frac{12}{5^{2} }[/tex]

= [tex]\frac{12}{5^{2} } +\frac{7\sqrt{7} }{3\sqrt{3} }[/tex]

[tex]5^{2} = 25[/tex]

= [tex]\frac{12}{25} + \frac{7\sqrt{7} }{3\sqrt{3} }[/tex]

[tex]\frac{\sqrt{7}.7 }{\sqrt{3} .3} =\frac{7\sqrt{21} }{9}[/tex]

= [tex]\frac{12}{25} + \frac{7\sqrt{21} }{9}[/tex]