Explicación paso a paso:
1a)
[tex]y = \frac{30x}{100} [/tex]
1b)
[tex]area = 3h[/tex]
1c)
[tex]perimetro = 6 + 2h[/tex]
1d)
[tex]y = 2(n + (n + 1))[/tex]
2a)
[tex]y = 3(x + \frac{1}{x} )[/tex]
2b)
[tex]y = 2(x + 5)[/tex]
2c)
[tex]y = \frac{ {x}^{2} }{5} [/tex]
2d)
[tex]area = \frac{ \frac{x}{2} \times x}{2} = \frac{ {x}^{2} }{4} [/tex]
3a)
[tex]y = \frac{(x + 3)}{2} [/tex]
3b)
[tex]area = \frac{x \times 2x}{3} = \frac{2 {x}^{2} }{3} [/tex]
3c)
[tex]y = {(x + (x + 1))}^{2} = {(2x + 1)}^{2} [/tex]
3d)
[tex]y = \frac{(x + \frac{x}{4}) }{2} = \frac{5x}{8} [/tex]
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Explicación paso a paso:
1a)
[tex]y = \frac{30x}{100} [/tex]
1b)
[tex]area = 3h[/tex]
1c)
[tex]perimetro = 6 + 2h[/tex]
1d)
[tex]y = 2(n + (n + 1))[/tex]
2a)
[tex]y = 3(x + \frac{1}{x} )[/tex]
2b)
[tex]y = 2(x + 5)[/tex]
2c)
[tex]y = \frac{ {x}^{2} }{5} [/tex]
2d)
[tex]area = \frac{ \frac{x}{2} \times x}{2} = \frac{ {x}^{2} }{4} [/tex]
3a)
[tex]y = \frac{(x + 3)}{2} [/tex]
3b)
[tex]area = \frac{x \times 2x}{3} = \frac{2 {x}^{2} }{3} [/tex]
3c)
[tex]y = {(x + (x + 1))}^{2} = {(2x + 1)}^{2} [/tex]
3d)
[tex]y = \frac{(x + \frac{x}{4}) }{2} = \frac{5x}{8} [/tex]