Question

Me ayudan a resolverlas plis con comprobación plis ​

Answer 1

Respuesta:

6x - 7 = 2x + 5

6x - 2x = 5 + 7

4x = 12

x = 12/4

x = 3

COMPROBAMOS :

18 - 7 = 6 + 5

11 = 11

.............................................

2x + 5 = 3x + 3

5 - 3 = 3x - 2x

2 = x

COMPROBAMOS:

4 + 5 = 6 + 3

9 = 9

..........................................

2x + 6 = x + 1

6 - 1 = x - 2x

5 = -x

x = -5

COMPROBAMOS:

-10 + 6 = -5 + 1

-4‬ = -4

Answer 2

Verified answer

a) 6x - 7 = 2x + 5

6x - 2x = 5 + 7

4x = 12

x = 12/4

x = 3

COMPROBAMOS :

18 - 7 = 6 + 5

11 = 11

.............................................

b) 2x + 5 = 3x + 3

  2x - 3x = 3 - 5

  -x = 3 -5

  -x = -2 Se cambia los signos en ambos miembros

   x = 2

COMPROBAMOS:

2(2) + 5 = 3(2) + 3

4 + 5 = 6 + 3

9 = 9

..........................................

c) 2x + 6 = x + 1

6 - 1 = x - 2x

5 = -x

x = -5

COMPROBAMOS:

-10 + 6 = -5 + 1

-4‬ = -4

..........................................

d)  [tex]\frac{1}{3}+5x = \frac{4}{3}[/tex]

   [tex]5x = \frac{4}{3} -\frac{1}{3}[/tex]

  [tex]5x = \frac{4-1}{3}[/tex]

  [tex]5x = \frac{3}{3}[/tex]

  5x = 1

   x = [tex]\frac{1}{5}[/tex]

  COMPROBAMOS:

  [tex]\frac{1}{3} + 5( \frac{1}{5} ) = \frac{4}{3}[/tex]   Desaparece [tex]5(\frac{}{5} )[/tex]

  [tex]\frac{1}{3} + 1 = \frac{4}{3}[/tex]

  [tex]\frac{1+3}{3} = \frac{4}{3}[/tex]

  [tex]\frac{4}{3} = \frac{4}{3}[/tex]

..........................................

e) 2x + 1 = [tex]\frac{5}{2}[/tex]

  [tex]2x = \frac{5}{2} -1[/tex]

  [tex]2x = \frac{5 -2}{2}[/tex]

 [tex]2x = \frac{3}{2}[/tex]

 [tex]2x : 2=\frac{3}{2} :2[/tex]

 [tex]x=\frac{3}{2} : 2[/tex]

[tex]x=\frac{3}{2} X \frac{1}{2}[/tex]

[tex]x= \frac{3}{4}[/tex]

COMPROBAMOS:

[tex]2(\frac{3}{4}) +1=\frac{5}{2}[/tex]       Simplifica    [tex]2 (\frac{}{4})[/tex]

[tex]\frac{3}{2} + 1=\frac{5}{2}[/tex]

[tex]\frac{3+2}{2}[/tex] = [tex]\frac{5}{2}[/tex]

[tex]\frac{5}{2} = \frac{5}{2}[/tex]

SI TE SIRVIO DAME CORONA