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Resolver.
x(x + 4) = 192
x² + 4x = 192
x² + 4x - 192 = 0 Factorizas trinomio de la forma x² + bx + c
(x + 16)(x - 12) = 0 Tiene como solución dos raices reales
x + 16 = 0
x = - 16
o
x - 12 = 0
x = 12
Solución.(16 , - 12)
x² 35 = 84
x² = 84 - 35
x² = 49
x = +/- √49
x = +/- 7
Solución.
(7 , - 7)
4x + 20 = 40
4x = 40 - 20
4x = 20
x = 20/4
x = 5
Solución
x = 5
3x + 41 = 68
3x = 68 - 41
3x = 27
x = 27/3
x = 9
Solución
x = 9
2x + 3y = 21 (1)
8x - 3y = 9 (2) Sumamos (1) y (2)
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10x = 30
x = 30/10
x = 3 Reemplazamos este valor en (1)
2x + 3y = 21
2 *3 + 3y = 21
6 + 3y = 21
3y = 21 - 6
3y = 15
y = 15/3
y = 5
Solución.
(3 , 5)