Question

Tiga buah pegas dengan konstanta k1=k2=k3=300N/m,bila ditarik gaya 30N ,maka pertambahan pegas bila:
a.disusun seri
b.disusun pararel

Answer 1

Verified answer

K₁ = k₂ = k₃ = 300 N/m
F = 30 N
x = ?

tetapan pegas disusun seri :
1/Ks = 1/300 + 1/300 + 1/300
1/ks = 3/300
ks = 300/3 = 100 N/m

F = k . x
30 = 100 . x
x = 30/100
x = 0,3 meter atau 30 cm

tetapan pegas disusun pararel :
Kp = 3×300
Kp = 900 N/m

F = k . x
30 = 900 . x
x = 30/900
x = 1/30 m
x = 30 cm