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nNH3 = 0,01 mol n H2SO4 = 0,004 mol (harusnya kalo di perhitungannya 0,005 mol , cuma kan gak mungkin jumlahnya bisa ngelebihin yang ada)
2NH3 + H2SO4 = (NH4)2SO4
Jawabannya :
9+log 1,5
pOH=6 -log2,5
pH,=8+log2,5