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= f(2x + 1) = (2x + 1)^2 - 1
=4x^2+4x+1 - 1 = 4x^2+4x
= 4(2^2) + 4(2) = 16 + 8 = 24
(f o g)(2) = f(g(x)) '
= f(2x + 1) = (2x + 1)^2 - 1
=4x^2+4x+1 - 1 = 4x^2+4x
= 4(2^2) + 4(2) = 16 + 8 = 24
maaf kalo salah