Question

Mau minta tolong dong, nomer 3 dan 4 beserta caranya

Answer 1

3.) 2 Liter Ba(OH)2 0,001 M

[OH^-] = b × Mb
[OH^-] = 2 × 0,001
[OH^-] = 0,002
[OH^-] = 2 × 10^-3

pOH = - log [OH^-]
pOH = - log 2 × 10^-3
pOH = 3 - log 2

pH = 14 - pOH
pH = 14 - (3 - log 2)
pH = 14 - 3 + log 2
pH = 11 + log 2


4.) Asam Sulfat (H2SO4) pH = 4 - log 2

pH = 4 - log 2

[H^+] = 2 × 10^-4

[H^+] = a × Ma
2 × 10^-4 = 2 × Ma
2 × 10^-4 / 2 = Ma
10^-4 = Ma
0,0001 = Ma

Konsentrasi H2SO4 tersebut adalah 0,0001 M