_____________________________
x² + y² + Ax + By + c = 0
—
x = 0, y = 5
0² + 5² + 0(A) + 5B + c = 0
25 + 5B + c = 0
x = -1, y = 0
(-1)² + 0² - A + 0(B) + c = 0
1 - A + c = 0
A = 1 + c
x = 5, y = 0
5² + 0² + 5A + 0(b) + c = 0
25 + 5A + c = 0
25 + 5(1 + c) + c = 0
25 + 5 + 5c + c = 0
6c = -30
c = -5
A = 1 - 5
A = -4
25 + 5B - 5 = 0
5B = -20
B = -4
x² + y² - 4x - 4y - 5 = 0
r² = (A/2)² + (B/2)² - c
r² = (-4/2)² + (-4/2)² - (-5)
r² = 4 + 4 + 5
r² = 13
r = √13 (C)
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❐ Lingkaran Analitika
_____________________________
x² + y² + Ax + By + c = 0
—
x = 0, y = 5
0² + 5² + 0(A) + 5B + c = 0
25 + 5B + c = 0
—
x = -1, y = 0
(-1)² + 0² - A + 0(B) + c = 0
1 - A + c = 0
A = 1 + c
—
x = 5, y = 0
5² + 0² + 5A + 0(b) + c = 0
25 + 5A + c = 0
25 + 5(1 + c) + c = 0
25 + 5 + 5c + c = 0
6c = -30
c = -5
—
A = 1 + c
A = 1 - 5
A = -4
—
25 + 5B + c = 0
25 + 5B - 5 = 0
5B = -20
B = -4
—
x² + y² + Ax + By + c = 0
x² + y² - 4x - 4y - 5 = 0
r² = (A/2)² + (B/2)² - c
r² = (-4/2)² + (-4/2)² - (-5)
r² = 4 + 4 + 5
r² = 13
r = √13 (C)