lim (1 - cos³ x) / (x tan x) x→0 = lim (1 - cos x) (1² + 1 . cos x + cos² x) / (x tan x) x→0 = lim ((1 - cos x) (1 + cos x + cos² x) (1 + cos x) / ((x tan x (1 + cos x))) x→0 = lim ((1 - cos² x) (cos² x + cos x + 1) / (x tan x (1 + cos x))) x→0 = lim ((sin² x) (cos² x + cos x + 1) / (x tan x (1 + cos x))) x→0 = lim (((sin² x) / (x tan x)) . ((cos² x + cos x + 1) / (1 + cos x)) x→0 = (cos² 0 + cos 0 + 1) / (1 + cos 0) = (1 + 1 + 1) / (1 + 1) = 3/2
Verified answer
Bab LimitMatematika SMA Kelas XI
lim (1 - cos³ x) / (x tan x)
x→0
= lim (1 - cos x) (1² + 1 . cos x + cos² x) / (x tan x)
x→0
= lim ((1 - cos x) (1 + cos x + cos² x) (1 + cos x) / ((x tan x (1 + cos x)))
x→0
= lim ((1 - cos² x) (cos² x + cos x + 1) / (x tan x (1 + cos x)))
x→0
= lim ((sin² x) (cos² x + cos x + 1) / (x tan x (1 + cos x)))
x→0
= lim (((sin² x) / (x tan x)) . ((cos² x + cos x + 1) / (1 + cos x))
x→0
= (cos² 0 + cos 0 + 1) / (1 + cos 0)
= (1 + 1 + 1) / (1 + 1)
= 3/2