odpowiedź C
[tex] \\ \sqrt[3]{8} - \frac{1}{ \sqrt{3} } {}^{2} + 4 \div \sqrt{36} = 2 - \frac{1}{3} + \frac{4}{6} = 1 \frac{2}{3} + \frac{2}{3} = 2 \frac{1}{3} [/tex]
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odpowiedź C
[tex] \\ \sqrt[3]{8} - \frac{1}{ \sqrt{3} } {}^{2} + 4 \div \sqrt{36} = 2 - \frac{1}{3} + \frac{4}{6} = 1 \frac{2}{3} + \frac{2}{3} = 2 \frac{1}{3} [/tex]