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Ax^2 + Bx + C = 0
syarat dua akar real berbeda, D > 0
B^2 - 4AC > 0
px^2 - 2(p - 1)x + p = 0
A = p
B = -2(p - 1)
C = p
B^2 - 4AC > 0
(-2(p - 1))^2 - 4(p)(p) > 0
(-2p + 2)^2 - 4p^2 > 0
4p^2 - 8p + 4 - 4p^2 > 0
-8p + 4 > 0
4 > 8p
8p < 4
p < 4/8
p < 1/2
tapi ingat, bentuk persamaan kuadrat, A tidak boleh nol, jadi p≠0
jadi, p < 1/2 dan p ≠ 0