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log[5^(2x+3)] = log[3^(x-1)]
(2x+3)log(5) = (x-1)log(3)
2xlog(5) + 3log(5) = xlog(3) - log(3)
2xlog(5) - xlog(3) = -log(3) - 3log(5)
x[2log(5) - log(3)] = -log(3) - 3log(5)
x = [-log(3) - 3log(5)] / [2log(5) - log(3)]
x = -2.574031268 / 0.920818754
x = -2.7953723