a. nilai y
QR² = PQ² + PR²
(y+4)² = y² + 16²
y²+8y +16 = y² + 256
8y +16 = 256
8y = 240
y = 30cm
b. luas segitiga PQR
luas segitiga = ½ alas × tinggi
= ½ y x 16
= ½ 30 x 16
= ½ 480
= 240cm²
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a. nilai y
QR² = PQ² + PR²
(y+4)² = y² + 16²
y²+8y +16 = y² + 256
8y +16 = 256
8y = 240
y = 30cm
b. luas segitiga PQR
luas segitiga = ½ alas × tinggi
= ½ y x 16
= ½ 30 x 16
= ½ 480
= 240cm²
semoga membantu..