Jawaban:
besar vektor = √[(y2-y1)²+(x2-x1)²]
= √[(3-1)² + (4-1)²]
= √(4+9)
= √13
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Verified answer
Jawaban:
besar vektor = √[(y2-y1)²+(x2-x1)²]
= √[(3-1)² + (4-1)²]
= √(4+9)
= √13