Respuesta:
#1
[tex]a)(5 \sqrt{3} + \sqrt{2} ) \sqrt{3} + 4 \sqrt{6} - 8 = \\ 15 + \sqrt{6} + 4 \sqrt{6} - 8 = \\ 7 + 5 \sqrt{6} [/tex]
[tex]b)7 \sqrt{2} + 3 \sqrt{20} - 2 \sqrt{50} + 4 \sqrt{5} = \\7 \sqrt{2} + + 6 \sqrt{5} - 10 \sqrt{2} + 4 \sqrt{5} = \\ - 3 \sqrt{2} + 10 \sqrt{5} [/tex]
#2
[tex]a)24 {m}^{6} \div 4 {m}^{2} + m( - {m}^{3} ) = \\ 6 {m}^{4} - {m}^{4} = \\ 5 {m}^{4} [/tex]
[tex]b)7 {a}^{3} + {a}^{2} (2a + 3a) = \\ 7 {a}^{3} + 2 {a}^{3} + 3 {a}^{3} = \\ 12 {a}^{3} [/tex]
#3
[tex]a) \frac{2}{5} {x}^{6} + \frac{3}{10} {x}^{4} = \frac{1}{10} {x}^{4} (4 {x}^{2} + 3)[/tex]
[tex]b)18 {a}^{4} - 6 {a}^{5} = 6 {a}^{4} (3 - a)[/tex]
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Verified answer
Respuesta:
#1
[tex]a)(5 \sqrt{3} + \sqrt{2} ) \sqrt{3} + 4 \sqrt{6} - 8 = \\ 15 + \sqrt{6} + 4 \sqrt{6} - 8 = \\ 7 + 5 \sqrt{6} [/tex]
[tex]b)7 \sqrt{2} + 3 \sqrt{20} - 2 \sqrt{50} + 4 \sqrt{5} = \\7 \sqrt{2} + + 6 \sqrt{5} - 10 \sqrt{2} + 4 \sqrt{5} = \\ - 3 \sqrt{2} + 10 \sqrt{5} [/tex]
#2
[tex]a)24 {m}^{6} \div 4 {m}^{2} + m( - {m}^{3} ) = \\ 6 {m}^{4} - {m}^{4} = \\ 5 {m}^{4} [/tex]
[tex]b)7 {a}^{3} + {a}^{2} (2a + 3a) = \\ 7 {a}^{3} + 2 {a}^{3} + 3 {a}^{3} = \\ 12 {a}^{3} [/tex]
#3
[tex]a) \frac{2}{5} {x}^{6} + \frac{3}{10} {x}^{4} = \frac{1}{10} {x}^{4} (4 {x}^{2} + 3)[/tex]
[tex]b)18 {a}^{4} - 6 {a}^{5} = 6 {a}^{4} (3 - a)[/tex]