Question

Massa barium klorida yang harus dilarutkan dalan 250 gram air sehingga mendidih pada suhu 101,56°C adalah.....(kb air=0,62; Cl=35,5; Ba=137)

Answer 1

Massa Bacl2 = gram
massa pelarut = 250
Δtb = 101,56-100 = 1,56
Mr BaCl2 = 208
i = 1 + (3-1)1 = 3

1,56 = (gram / 208 × 1000/250) × 0,62 × 3
1,56 = gram / 208 × 4×1,86
gram = 1,56  × 208 / 7.44
=43,6 gram