Jawaban:
Mencari jenis segitiga
[tex] \sf = a² + b² = c² \: \: \: \: \: \: \: \: \: \\ \sf = 13² + 11² = 18² \: \: \\ \sf = 169 + 121 = 324 \\ \sf = 290 < 324 \: \: \: \: \: \: \: \: \: \: \: \: [/tex]
Jenis segitiga Tumpul
Menentukan triple Pythagoras
[tex] \sf = a² + b² = c² \: \: \: \: \: \: \: \: \: \\ \sf = 16² + 12² = 20² \: \: \\ \sf = 256 + 144 = 400 \\ \sf = 400 = 400 \: \: \: \: \: \: \: \: \: \: \: \: [/tex]
Termasuk Triple Pythagoras
Panjang sisi miring CD
[tex] \sf {CD}^{2} = {BD}^{2} + { BC}^{2} \\ \sf {CD}^{2} = {12}^{2} + {9}^{2} \: \: \: \: \: \\ \sf {CD}^{2} = 144 + 81 \: \: \: \: \\ \sf {CD}^{2} = 225 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf CD = \sqrt{225} \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf {CD} = 15 \: cm \: \: \: \: \: \: \: \: \: \: \: [/tex]
Keliling bangun ACDE
[tex] \sf Keliling = AB + ED + CD + BC \\ \sf Keliling = 12 + 12 + 15 + 9 \: \: \: \: \: \: \: \: \\ \sf Keliling = 12 + 12 + 24 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf Keliling = 12 + 36 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf Keliling = 48 \: cm \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]
2) 13² + 11² = 18²
(13(13) + (11(11) = (18(18)
169 + 121 = 324
290 < 324
∆TUMPUL
3) 16² + 12² = 20²
(16(16) + (12(12) = (20(20)
256 + 144 = 400
400 = 400
MERUPAKAN TRIPLE PYTHAGORAS
4) CD = √12² + 9²
= √(12(12) + (9(9)
= √144 + 81
= √225
= √15²
= 15
K = (12 + 12 + 15 + 9)
= (24 + 24)
= 48 CM
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Jawaban:
Nomor 2.
Mencari jenis segitiga
[tex] \sf = a² + b² = c² \: \: \: \: \: \: \: \: \: \\ \sf = 13² + 11² = 18² \: \: \\ \sf = 169 + 121 = 324 \\ \sf = 290 < 324 \: \: \: \: \: \: \: \: \: \: \: \: [/tex]
Jenis segitiga Tumpul
Nomor 3.
Menentukan triple Pythagoras
[tex] \sf = a² + b² = c² \: \: \: \: \: \: \: \: \: \\ \sf = 16² + 12² = 20² \: \: \\ \sf = 256 + 144 = 400 \\ \sf = 400 = 400 \: \: \: \: \: \: \: \: \: \: \: \: [/tex]
Termasuk Triple Pythagoras
Nomor 4.
Panjang sisi miring CD
[tex] \sf {CD}^{2} = {BD}^{2} + { BC}^{2} \\ \sf {CD}^{2} = {12}^{2} + {9}^{2} \: \: \: \: \: \\ \sf {CD}^{2} = 144 + 81 \: \: \: \: \\ \sf {CD}^{2} = 225 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf CD = \sqrt{225} \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf {CD} = 15 \: cm \: \: \: \: \: \: \: \: \: \: \: [/tex]
Keliling bangun ACDE
[tex] \sf Keliling = AB + ED + CD + BC \\ \sf Keliling = 12 + 12 + 15 + 9 \: \: \: \: \: \: \: \: \\ \sf Keliling = 12 + 12 + 24 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf Keliling = 12 + 36 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf Keliling = 48 \: cm \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]
2) 13² + 11² = 18²
(13(13) + (11(11) = (18(18)
169 + 121 = 324
290 < 324
∆TUMPUL
3) 16² + 12² = 20²
(16(16) + (12(12) = (20(20)
256 + 144 = 400
400 = 400
MERUPAKAN TRIPLE PYTHAGORAS
4) CD = √12² + 9²
= √(12(12) + (9(9)
= √144 + 81
= √225
= √15²
= 15
K = (12 + 12 + 15 + 9)
= (24 + 24)
= 48 CM