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Mn = 4
b. K + Mn + 4( -2) = 0
1 + Mn -8 = 0
Mn = 7
c. Mn + 6 + 4(-2) = 0
Mn - 2 = 0
Mn = 2
d. 2(1) + Mn + 4(-2) = 0
2 + Mn -8 = 0
Mn = 6
e. Mn -2 = 0
Mn = 2
jadi bilok tertinggi : b. KMnO4